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350-401 PDF DEMO:

QUESTION NO: 1
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.

QUESTION NO: 2
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID

QUESTION NO: 3
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.

QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D

QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.

試験が更新されているうちに、我々はCiscoのSalesforce CRT-261試験の資料を更新し続けています。 CIPS L4M4 - それで、「就職難」の場合には、他の人々と比べて、あなたはずっと優位に立つことができます。 Juniper JN0-253 - 自分の幸せは自分で作るものだと思われます。 試用した後、我々のISACA COBIT-Design-and-Implementation問題集はあなたを試験に順調に合格させると信じられます。 あなたは弊社の高品質Cisco SAP C-FIORD-2502試験資料を利用して、一回に試験に合格します。

Updated: May 28, 2022

350-401問題数 - 350-401関連資格試験対応 & Implementing Cisco Enterprise Network Core Technologies 350-401 Encor

PDF問題と解答

試験コード:350-401
試験名称:Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)
最近更新時間:2025-06-12
問題と解答:全 335
Cisco 350-401 最新試験

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模擬試験

試験コード:350-401
試験名称:Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)
最近更新時間:2025-06-12
問題と解答:全 335
Cisco 350-401 合格率書籍

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オンライン版

試験コード:350-401
試験名称:Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)
最近更新時間:2025-06-12
問題と解答:全 335
Cisco 350-401 試験感想

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350-401 受験トレーリング

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