世の中に去年の自分より今年の自分が優れていないのは立派な恥です。それで、IT人材として毎日自分を充実して、350-401最新な問題集問題集を学ぶ必要があります。弊社の350-401最新な問題集問題集はあなたにこのチャンスを全面的に与えられます。 それはShobhadoshiが提供した試験問題資料は絶対あなたが試験に合格することを保証しますから。なんでそうやって言ったのはShobhadoshiが提供した試験問題資料は最新な資料ですから。 また、350-401最新な問題集問題集に疑問があると、メールで問い合わせてください。

CCNP Enterprise 350-401 弊社の商品が好きなのは弊社のたのしいです。

ShobhadoshiのCiscoの350-401 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)最新な問題集試験トレーニング資料は間違いなく最高のトレーニング資料ですから、それを選ぶことはあなたにとって最高の選択です。 Shobhadoshi を選択して１００％の合格率を確保することができて、もし試験に失敗したら、Shobhadoshiが全額で返金いたします。

あなたは新しい旅を始めることができ、人生の輝かしい実績を実現することができます。他の人の成功を見上げるよりも、自分の成功への努力をしたほうがよいです。ShobhadoshiのCiscoの350-401最新な問題集試験トレーニング資料はあなたの成功への第一歩です。

Cisco 350-401最新な問題集 - Shobhadoshiを選んだら、成功への扉を開きます。

安全で信頼できるウェブサイトとして、あなたの個人情報の隠しとお支払いの安全性を保障していますから、弊社のCiscoの350-401最新な問題集試験ソフトを安心にお買いください。弊社のShobhadoshiは最大なるIT試験のための資料庫ですので、ほかの試験に興味があるなら、Shobhadoshiで探したり、弊社の係員に問い合わせたりすることができます。心よりご成功を祈ります。

Shobhadoshiはあなたが試験に合格するのを助けることができるだけでなく、あなたは最新の知識を学ぶのを助けることもできます。このような素晴らしい資料をぜひ見逃さないでください。

350-401 PDF DEMO:

QUESTION NO: 1
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID

QUESTION NO: 2
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.

QUESTION NO: 3
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.

QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D

QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.

CiscoのISACA CISM試験に合格するのは最良の方法の一です。 あるいは、無料で試験Cisco 300-510問題集を更新してあげるのを選択することもできます。 CiscoのAmazon SAA-C03-KR試験の資料のいくつかのバーションのデモは我々のウェブサイトで無料でダウンロードできます。 Microsoft MB-820 - なぜ受験生のほとんどはShobhadoshiを選んだのですか。 その他、Snowflake COF-C02問題集の更新版を無料に提供します。

Updated: May 28, 2022