Shobhadoshiは長年にわたってずっとIT認定試験に関連する350-401受験記参考書を提供しています。これは受験生の皆さんに検証されたウェブサイトで、一番優秀な試験350-401受験記問題集を提供することができます。Shobhadoshiは全面的に受験生の利益を保証します。 がむしゃらに試験に関連する知識を勉強しているのですか。それとも、効率が良い試験350-401受験記参考書を使っているのですか。 うちのCiscoの350-401受験記試験問題集は完全な無制限のダンプが含まれているから、使ったら気楽に試験に合格することができます。

CCNP Enterprise 350-401 まだ何を待っていますか。

うちのCiscoの350-401 - Implementing Cisco Enterprise Network Core Technologies (350-401 ENCOR)受験記試験トレーニング資料は豊富な経験を持っている専門家が長年の研究を通じて開発されたものです。 それは正確性が高くて、カバー率も広いです。あなたはShobhadoshiの学習教材を購入した後、私たちは一年間で無料更新サービスを提供することができます。

信じられないなら、弊社のデモをやってみて、Ciscoの350-401受験記試験問題集を体験することができます。試して我々専門家たちの真面目さを感じられています。Ciscoの350-401受験記試験のほかの試験に参加するつもりでしたら、あなたも弊社のShobhadoshiでふさわしいソフトを探すことができます。

CiscoのCisco 350-401受験記試験の準備は重要です。

社会と経済の発展につれて、多くの人はIT技術を勉強します。なぜならば、IT職員にとって、Ciscoの350-401受験記資格証明書があるのは肝心な指標であると言えます。自分の能力を証明するために、350-401受験記試験に合格するのは不可欠なことです。弊社の350-401受験記真題を入手して、試験に合格する可能性が大きくなります。

ほかの人はあちこちCiscoの350-401受験記試験の資料を探しているとき、あなたは問題集の勉強を始めました。準備の段階であなたはリーダーしています。

350-401 PDF DEMO:

QUESTION NO: 1
What is the correct EBGP path attribute list, ordered from most preferred to the least preferred, that the BGP best-path algorithm uses?
A. weight, local preference, AS path, MED
B. weight, AS path, local preference, MED
C. local preference, weight MED, AS path
D. local preference, weight, AS path, MED
Answer: A
Explanation:
Path Selection Attributes: Weight > Local Preference > Originate > AS Path > Origin > MED > External
> IGP Cost > eBGP Peering > Router ID

QUESTION NO: 2
Which standard access control entry permits from odd-numbered hosts in the 10.0.0.0/24 subnet?
A. Permit 10.0.0.0.255.255.255.254
B. Permit 10.0.0.1.0.0.0.254
C. Permit 10.0.0.1.0.0.0.0
D. Permit 10.0.0.0.0.0.0.1
Answer: B
Explanation:
Remember, for the wildcard mask, 1's are I DON'T CARE, and 0's are I CARE. So now let's analyze a simple ACL:
access-list 1 permit 172.23.16.0 0.0.15.255
Two first octets are all 0's meaning that we care about the network 172.23.x.x. The third octet of the wildcard mask, 15 (0000 1111 in binary), means that we care about first 4 bits but don't care about last 4 bits so we allow the third octet in the form of 0001xxxx (minimum:00010000 = 16; maximum:
0001111 = 31).
The fourth octet is 255 (all 1 bits) that means I don't care.
Therefore network 172.23.16.0 0.0.15.255 ranges from 172.23.16.0 to 172.23.31.255.
Now let's consider the wildcard mask of 0.0.0.254 (four octet: 254 = 1111 1110) which means we only care the last bit. Therefore if the last bit of the IP address is a "1" (0000 0001) then only odd numbers are allowed. If the last bit of the IP address is a "0" (0000 0000) then only even numbers are allowed.
Note: In binary, odd numbers are always end with a "1" while even numbers are always end with a
"0".
Therefore in this question, only the statement "permit 10.0.0.1 0.0.0.254" will allow all odd- numbered hosts in the 10.0.0.0/24 subnet.

QUESTION NO: 3
Which statement explains why Type 1 hypervisor is considered more efficient than Type 2 hypervisor?
A. Type 1 hypervisor enables other operating systems to run on it
B. Type 1 hypervisor runs directly on the physical hardware of the host machine without relying on the underlying OS
C. Type 1 hypervisor relics on the existing OS of the host machine to access CPU, memory, storage, and network resources.
D. Type 1 hypervisor is the only type of hypervisor that supports hardware acceleration techniques
Answer: B
Explanation:
There are two types of hypervisors: type 1 and type 2 hypervisor.
In type 1 hypervisor (or native hypervisor), the hypervisor is installed directly on the physical server.
Then instances of an operating system (OS) are installed on the hypervisor. Type 1 hypervisor has direct access to the hardware resources. Therefore they are more efficient than hosted architectures.
Some examples of type 1 hypervisor are VMware vSphere/ESXi, Oracle VM Server, KVM and
Microsoft Hyper-V.
In contrast to type 1 hypervisor, a type 2 hypervisor (or hosted hypervisor) runs on top of an operating system and not the physical hardware directly. A big advantage of Type 2 hypervisors is that management console software is not required.

QUESTION NO: 4
Which access controls list allows only TCP traffic with a destination port range of 22-433, excluding port 80?
A. Deny tcp any any ne 80
Permit tcp any any range 22 443
B. Permit tcp any any ne 80
C. Permit tco any any range 22 443
Deny tcp any any eq 80
D. Deny tcp any any eq 80
Permit tco any any gt 21 it 444
Answer: D

QUESTION NO: 5
Which statement about multicast RPs is true?
A. RPs are required for protocol independent multicast sparse mode and dense mode.
B. By default, the RP is needed only to start new sessions with sources and receivers.
C. By default, the RP is needed periodically to maintain sessions with sources and receivers
D. RPs are required only when using protocol independent multicast dense mode.
Answer: B
Explanation:
A rendezvous point (RP) is required only in networks running Protocol Independent Multicast sparse mode (PIM-SM).
By default, the RP is needed only to start new sessions with sources and receivers.
Reference:
https://www.cisco.com/c/en/us/td/docs/ios/solutions_docs/ip_multicast/White_papers/rps.html
For your information, in PIM-SM, only network segments with active receivers that have explicitly requested multicast data will be forwarded the traffic. This method of delivering multicast data is in contrast to the PIM dense mode (PIM-DM) model. In PIM-DM, multicast traffic is initially flooded to all segments of the network. Routers that have no downstream neighbors or directly connected receivers prune back the unwanted traffic.

あなたにCisco　PMI CAPM試験に関する最新かつ最完備の資料を勉強させ、試験に合格させることだと信じます。 我が社のEMC D-MSS-DS-23問題集は必ずあなたの成功へ道の助力になれます。 周りの多くの人は全部Cisco　Amazon ANS-C01資格認定試験にパースしまして、彼らはどのようにできましたか。 我々の問題集によって、ほとんどの受験生は大方の人から見る大変なCisco　GIAC GSOM試験にうまく合格しました。 そうすれば、あなたは簡単にAmazon AWS-Solutions-Architect-Associate-KR復習教材のデモを無料でダウンロードできます。

Updated: May 28, 2022