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CCNP 642-902 不相信嗎？Shobhadoshi的考古題就是這樣的資料。

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所以，Shobhadoshi的Cisco 642-902考古題更新考古題吧。

Shobhadoshi的642-902考古題更新考古題有著讓你難以置信的命中率。這個考古題包含實際考試中可能出現的一切問題。因此，只要你好好學習這個考古題，通過642-902考古題更新考試就會非常容易。作為Cisco的一項重要的考試，642-902考古題更新考試的認證資格可以給你帶來很大的好處。所以你絕對不能因為失去這次可以成功通過考試的機會。Shobhadoshi承諾如果考試失敗就全額退款。為了你能順利通過642-902考古題更新考試，趕緊去Shobhadoshi的網站瞭解更多的資訊吧。

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642-902 PDF DEMO:

QUESTION NO: 1
What are the two reasons for the appearance of 0.0.0.0 as the next hop for a network in the show ip bgp command output? (Choose two.)
A. The network was originated via redistribution of an interior gateway protocol into BGP.
B. The network was defined by a static route.
C. The network was originated via a network or aggregate command.
D. The network was learned via EBGP.
E. The network was learned via IBGP.
Answer: AC

QUESTION NO: 2
Refer to the exhibit.
Which two statements are true about the partial configuration that is provided. (Choose two.)
A. All the configured neighbors are in autonomous system 100.
B. The peer group shortens the IBGP configuration.
C. The peer group shortens the EBGP configuration.
D. Only the outgoing filters are applied to BGP updates.
E. Three AS-path filters are applied to each BGP neighbor.
Answer: AB

QUESTION NO: 3
Which three restrictions apply to OSPF stub areas? (Choose three.)
A. No virtual links are allowed.
B. The area cannot be a backbone area.
C. Redistribution is not allowed unless the packet is changed to a type 7 packet.
D. The area has no more than 10 routers.
E. No autonomous system border routers are allowed.
F. Interarea routes are suppressed.
Answer: ABE

QUESTION NO: 4
Refer to the exhibit.
Which two statements are correct? (Choose two.)
A. All six routes will be installed in the routing table.
B. Two routes will be installed in the routing table.
C. Four routes will be installed in the routing table.
D. All the routes were redistributed into BGP from an IGP.
E. All the routes were originated by BGP with the network command.
Answer: CD

QUESTION NO: 5
What are two rules for compacting IPv6 addresses? (Choose two.)
A. The maximum number of times a double colon can replace a 16-bit segment that consists of all zeroes is two.
B. The leading zeroes in any 16-bit segment do not have to be written.
C. Every 16-bit segment that consists of all zeroes can be represented with a single colon.
D. The trailing zeroes in any 16-bit segment do not have to be written.
E. Any single, continuous string of one or more 16-bit segments that consists of all zeroes can be represented with a double colon.
F. Two zeroes in the middle of any 16-bit segment do not have to be written.
Answer: BE

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Updated: May 28, 2022