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QUESTION NO: 1
Examine the structure of the PROGRAMS table:
Which two SQL statements would execute successfully? (Choose two.)
A. SELECT TO_DATE(NVL(SYSDATE-END_DATE,SYSDATE))FROM programs;
B. SELECT NVL(ADD_MONTHS(END_DATE,1)SYSDATE)FROM programs;
C. SELECT NVL(TO_CHAR(MONTHS_BETWEEN(start-date,end_date)),'Ongoing')FROM programs;
D. SELECT NVL(MONTHS_BETWEEN(start_date,end_date),'Ongoing')FROM programs;
Answer: A,C
QUESTION NO: 2
Which three SQL statements would display the value 1890.55 as $1,890.55? (Choose three.)
A. SELECT TO_CHAR (1890.55, '$99,999D99')FROM DUAL;
B. SELECT TO_CHAR (1890.55, '$99G999D00')FROM DUAL
C. SELECT TO_CHAR (1890.55, '$0G000D00')FROM DUAL;
D. SELECT TO_CHAR (1890.55, '$9,999V99')FROM DUAL;
E. SELECT TO_CHAR (1890.55, '$99G999D99')FROM DUAL
Answer: B,C,E
QUESTION NO: 3
You issued the following command:
SQL> DROP TABLE employees;
Which three statements are true? (Choose three.)
A. All uncommitted transactions are committed.
B. The space used by the employees table is reclaimed immediately.
C. The employees table is moved to the recycle bin
D. Sequences used in the employees table become invalid.
E. All indexes and constraints defined on the table being dropped are also dropped.
F. The employees table can be recovered using the rollback command.
Answer: A,C,E
QUESTION NO: 4
Which three statements are true about time zones, date data types, and timestamp data types in an Oracle database?
A. A TIMESTAMP data type column contains information about year, month, and day.
B. A TIMESTAMP WITH LOCAL TIMEZONE data type column is stored in the database using the time zone of the session that inserted the row.
C. The CURRENT_TIMESTAMP function returns data without time zone information.
D. The SESSIONTIMEZONE function can return an offset from Universal Coordinated Time (UTC).
E. The DBTIMEZONE function can return an offset from Universal Coordinated Time (UTC).
Answer: C,D,E
QUESTION NO: 5
View the Exhibit and examine the structure of the ORDER_ITEMS table.
Examine the following SQL statement:
SELECT order_id, product_id, unit_price
FROM order_items
WHERE unit_price =
(SELECT MAX(unit_price)
FROM order_items
GROUP BY order_id);
You want to display the PRODUCT_ID of the product that has the highest UNIT_PRICE per ORDER_ID.
What correction should be made in the above SQL statement to achieve this?
A. Replace = with the >ANY operator
B. Replace = with the IN operator
C. Remove the GROUP BY clause from the subquery and place it in the main query
D. Replace = with the >ALL operator
Answer: B
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Updated: May 28, 2022