Shobhadoshi為考生提供真正有效的考試學習資料，充分利用我們的Oracle 1z0-071最新考證題庫問題和答案，可以節約您的時間和金錢。考生需要深入了解學習我們的1z0-071最新考證考古題，為獲得認證奠定堅實的基礎，您會發現這是真實有效的，全球的IT人員都在使用我們的1z0-071最新考證題庫資料。快來購買1z0-071最新考證考古題吧！如果您想要真正的考試模擬，那就選擇我們的1z0-071最新考證題庫在線測試引擎版本，支持多個設備安裝，還支持離線使用。 在認證IT行業已經有很久了，所以才有今天赫赫有名的地位及知名度，這都是幫助那些考生而得到的結果。我們的Oracle的1z0-071最新考證考試認證培訓資料包含試題及答案，這些資料是由我們資深的IT專家團隊通過自己的知識及不斷摸索的經驗而研究出來的，它的內容有包含真實的考試題，如果你要參加Oracle的1z0-071最新考證考試認證，選擇Shobhadoshi是無庸置疑的選擇。 客戶成功購買我們的1z0-071最新考證題庫資料之后，都將享受一年的免費更新服務，一年之內，如果您購買的1z0-071最新考證學習資料更新了，我們將免費發送最新版本的到您的郵箱。
Shobhadoshi能為你提供一個可靠而全面的關於通過Oracle 1z0-071 - Oracle Database SQL最新考證 認證考試的方案。 一生輾轉千萬裏，莫問成敗重幾許，得之坦然，失之淡然，與其在別人的輝煌裏仰望，不如親手點亮自己的心燈，揚帆遠航。Shobhadoshi Oracle的最新 1z0-071 考題考試培訓資料將是你成就輝煌的第一步，有了它，你一定會通過眾多人都覺得艱難無比的Oracle的最新 1z0-071 考題考試認證，獲得了這個認證，你就可以在你人生中點亮你的心燈，開始你新的旅程，展翅翱翔，成就輝煌人生。
Shobhadoshi是個能夠加速你通過Oracle 1z0-071最新考證認證考試的網站。我們的Oracle 1z0-071最新考證 認證考試的考古題是Shobhadoshi的專家不斷研究出來的。當你還在為通過Oracle 1z0-071最新考證 認證考試而奮鬥時，選擇Shobhadoshi的Oracle 1z0-071最新考證 認證考試的最新考古題將給你的復習備考帶來很大的幫助。
Oracle 1z0-071最新考證認證考試是IT人士在踏上職位提升之路的第一步。通過了Oracle 1z0-071最新考證 認證考試是你邁向事業頂峰的的墊腳石。Shobhadoshi可以幫助你通過Oracle 1z0-071最新考證認證考試。
在這裏我想說的就是怎樣才能更有效率地準備1z0-071最新考證考試，並且一次就通過考試拿到考試的認證資格。Oracle的認證考試現在是很有人氣的考試。
QUESTION NO: 1
View the exhibit and examine the structure of the SALES, CUSTOMERS, PRODUCTS and TIMES tables.
The PROD_ID column is the foreign key in the SALES table referencing the PRODUCTS table.
The CUST_ID and TIME_ID columns are also foreign keys in the SALES table referencing the
CUSTOMERS and TIMES tables, respectively.
Examine this command:
CREATE TABLE new_sales (prod_id, cust_id, order_date DEFAULT SYSDATE)
AS
SELECT prod_id, cust_id, time_id
FROM sales;
Which statement is true?
A. The NEW_SALES table would not get created because the DEFAULT value cannot be specified in the column definition.
B. The NEW_SALES table would not get created because the column names in the CREATE TABLE command and the SELECT clause do not match.
C. The NEW_SALES table would get created and all the NOT NULL constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the NEW_SALES table.
D. The NEW_SALES table would get created and all the FOREIGN KEY constraints defined on the selected columns from the SALES table would be created on the corresponding columns in the
NEW_SALES table.
Answer: C
QUESTION NO: 2
View the Exhibit and examine the structure of the CUSTOMERS table.
Evaluate the following SQL statement:
Which statement is true regarding the outcome of the above query?
A. It returns an error because WHERE and HAVING clauses cannot be used in the same SELECT statement.
B. It returns an error because the BETWEEN operator cannot be used in the HAVING clause.
C. It returns an error because WHERE and HAVING clauses cannot be used to apply conditions on the same column.
D. It executes successfully.
Answer: D
QUESTION NO: 3
The user SCOTT who is the owner of ORDERS and ORDER_ITEMS tables issues this GRANT command:
GRANT ALL
ON orders, order_items
TO PUBLIC;
What must be done to fix the statement?
A. Separate GRANT statements are required for the ORDERS and ORDER_ITEMS tables.
B. PUBLIC should be replaced with specific usernames.
C. ALL should be replaced with a list of specific privileges.
D. WITH GRANT OPTION should be added to the statement.
Answer: A
Explanation:
http://docs.oracle.com/javadb/10.8.3.0/ref/rrefsqljgrant.html
QUESTION NO: 4
Examine the structure of the EMPLOYEES table:
There is a parent/child relationship between EMPLOYEE_ID and MANAGER_ID.
You want to display the name, joining date, and manager for all employees. Newly hired employees are yet to be assigned a department or a manager. For them, 'No Manager' should be displayed in the MANAGER column.
Which SQL query gets the required output?
A. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
RIGHT OUTER JOIN employees mON (e.manager_id = m.employee_id);
B. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
JOIN employees mON (e.manager_id = m.employee_id);
C. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
NATURAL JOIN employees mON (e.manager_id = m.employee_id).
D. SELECT e.last_name, e.hire_date, NVL(m.last_name, 'No Manager') ManagerFROM employees e
LEFT OUTER JOIN employees mON (e.manager_id = m.employee_id);
Answer: D
QUESTION NO: 5
Examine this SQL statement:
Which two are true?
A. The subquery is not a correlated subquery
B. The subquery is executed before the UPDATE statement is executed
C. The UPDATE statement executes successfully even if the subquery selects multiple rows
D. The subquery is executed for every updated row in the ORDERS table
E. All existing rows in the ORDERS table are updated
Answer: D,E
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Updated: May 28, 2022