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QUESTION NO: 1
Given the code fragment:
var pool = Executors.newFixedThreadPool(5);
Future outcome = pool.submit(() -> 1);
Which type of lambda expression is passed into submit()?
A. java.util.function.Predicate
B. java.util.function.Function
C. java.lang.Runnable
D. java.util.concurrent.Callable
Answer: D
Reference:
https://www.codota.com/code/java/methods/java.util.concurrent.Executors/newFixedThreadPool
QUESTION NO: 2
Given:
Which two are secure serialization of these objects? (Choose two.)
A. Implement only writeReplace to replace the instance with a serial proxy and not readResolve.
B. Define the serialPersistentFields array field.
C. Implement only readResolve to replace the instance with a serial proxy and not writeReplace.
D. Declare fields transient.
E. Make the class abstract.
Answer: B,C
QUESTION NO: 3
Given:
var data = new ArrayList<>();
data.add("Peter");
data.add(30);
data.add("Market Road");
data.set(1, 25);
data.remove(2);
data.set(3, 1000L);
System.out.print(data);
What is the output?
A. [Peter, 30, Market Road]
B. An exception is thrown at run time.
C. [Peter, 25, null, 1000]
D. [Market Road, 1000]
Answer: B
Explanation:
QUESTION NO: 4
Given:
List<String> longlist = List.of("Hello","World","Beat");
List<String> shortlist = new ArrayList<>();
Which code fragment correctly forms a short list of words containing the letter "e"?
A. Option B
B. Option A
C. Option D
D. Option C
Answer: D
QUESTION NO: 5
Given:
and:
Which code, when inserted on line 10, prints the number of unique localities from the roster list?
A. map(e -> e.getLocality())
.count();
B. .filter(Employee::getLocality)
.distinct()
.count();
C. .map(e -> e.getLocality())
.collect(Collectors.toSet())
.count();
D. .map(Employee::getLocality)
.distinct()
.count();
Answer: B
Reference:
https://developer.android.com/reference/android/location/Address
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Updated: May 28, 2022
Exam Code: 1Z0-816
Exam Name: Java SE 11 Programmer II
Updated: June 11, 2025
Total Q&As:80
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Total Q&As:80
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Exam Code: 1Z0-816
Exam Name: Java SE 11 Programmer II
Updated: June 11, 2025
Total Q&As:80
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