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QUESTION NO: 1
Examine the domain diagram:
You are asked to write a WLST script that will print the current available heap size for server04.
Assuming:
* all servers are running
* you have just started an offline, interactive WLST session
* a domain-scoped node manager is running on each machine, listening o port :5556
* the username/password "weblogic/Welcome1" maps to a valid domain administrator and Node
Manager client Which two code options will accomplish this task? (Choose two.)
A. connect('weblogic','Welcome1','host00.acme.com:7001')domainRuntime()x = getMBean('/ServerRuntimes/server04/JVMRuntime/server04')print x.getHeapFreeCurrent()
B. connect('weblogic','Welcome1','host00.acme.com:7001')serverRuntime()x = getMBean('/JVMRuntime/server04')print x.getHeapFreeCurrent()
C.
nmConnect('weblogic','Welcome1','host02.acme.com:5556')serverRuntimes()x=getMBean('/server04
/JV x.getHeapFreeCurrent()
D.
nmConnect('weblogic','Welcome1','host00.acme.com:5556')domainRuntime()x=getMBean('/ServerR un x.getHeapFreeCurrent()
E. connect('weblogic','Welcome1','host02.acme.com:7201')serverRuntime()x = getMBean('/JVMRuntime/server04')print x.getHeapFreeCurrent()
Answer: A,E

QUESTION NO: 2
You are in the process of validating the architecture of a domain that will serve applications to automate various business activities for a large retailer. The applications rely heavily on JMS and you need to pay special attention to JMS storage. You argue in favor of JDBC-based storage rather than file storage.
Your management has asked you to come up with a few key points about why this persistence option would be a better option in case of failure.
Which two justifications would support your choice? (Choose two.)
A. It is easier to recover data from a database rather than from a file.
B. JDBC-based stores are the default choice when creating a new persistent store so it must be an
Oracle-recommended choice.
C. JDBC-based stores can be accessed by any client and usually do not reside on the machine that hosts the server.
D. JDBC-based stores offer better throughput than file stores.
Answer: B,D

QUESTION NO: 3
I am sending a set of ten JMS messages. I want all of these messages to be sent successfully or none at all.
Which JMS Session feature is most suitable for implementing such a scenario? (Choose the best answer.)
A. Unit of Order
B. Persistent Session
C. Store and Forward
D. Server affinity
E. Transacted Session
Answer: E

QUESTION NO: 4
Which two objects can be considered potential clients of a Node Manager? (Choose two.)
A. an administration server
B. any other Node Manager
C. a remote JMS client
D. the weblogic.Deployer utility
E. a WLST session
F. an HTTP server
Answer: A,E
Explanation
A Node Manager client can be local or remote to the Node Managers with which it communicates.
You access either version of Node Manager-the Java version or the script-based (SSH) version-from the following clients:
A: an administration server
B: WLST commands and scripts-WLST offline serves as a Node Manager command-line interface that can run in the absence of a running Administration Server.

QUESTION NO: 5
What is the difference between a WebLogic Diagnostic Framework (WLDF) watch and a notification?
(Choose the best answer.)
A. A watch compares WLDF instrumentation data to a rule and sends a notification SMS text message.
B. A notification compares WebLogic log data to a rule and notifies a watch when the rule is true.
C. A watch compares WLDF metric data to a rule and triggers a certain notification action.
D. A notification compares WLDF instrumentation data to a rule and notifies a watch when the rule is true.
Answer: C

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Updated: May 28, 2022

1Z0-134 Study Dumps - Oracle WebLogic Server 12C: Advanced Administrator II Valid Test Vce

PDF Questions & Answers

Exam Code: 1z0-134
Exam Name: Oracle WebLogic Server 12c: Advanced Administrator II
Updated: June 15, 2025
Total Q&As:127
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Exam Code: 1z0-134
Exam Name: Oracle WebLogic Server 12c: Advanced Administrator II
Updated: June 15, 2025
Total Q&As:127
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Exam Code: 1z0-134
Exam Name: Oracle WebLogic Server 12c: Advanced Administrator II
Updated: June 15, 2025
Total Q&As:127
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